2x^2+3y^2-4=0

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Solution for 2x^2+3y^2-4=0 equation:


Simplifying
2x2 + 3y2 + -4 = 0

Reorder the terms:
-4 + 2x2 + 3y2 = 0

Solving
-4 + 2x2 + 3y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 2x2 + 4 + 3y2 = 0 + 4

Reorder the terms:
-4 + 4 + 2x2 + 3y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 2x2 + 3y2 = 0 + 4
2x2 + 3y2 = 0 + 4

Combine like terms: 0 + 4 = 4
2x2 + 3y2 = 4

Add '-3y2' to each side of the equation.
2x2 + 3y2 + -3y2 = 4 + -3y2

Combine like terms: 3y2 + -3y2 = 0
2x2 + 0 = 4 + -3y2
2x2 = 4 + -3y2

Divide each side by '2'.
x2 = 2 + -1.5y2

Simplifying
x2 = 2 + -1.5y2

Reorder the terms:
-2 + x2 + 1.5y2 = 2 + -1.5y2 + -2 + 1.5y2

Reorder the terms:
-2 + x2 + 1.5y2 = 2 + -2 + -1.5y2 + 1.5y2

Combine like terms: 2 + -2 = 0
-2 + x2 + 1.5y2 = 0 + -1.5y2 + 1.5y2
-2 + x2 + 1.5y2 = -1.5y2 + 1.5y2

Combine like terms: -1.5y2 + 1.5y2 = 0.0
-2 + x2 + 1.5y2 = 0.0

The solution to this equation could not be determined.

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